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a-b-c-are-pythagorean-triples-For-the-following-values-determinant-a-b-c-5-12-13-a-2-b-c-5-2-12-13-25-determinant-a-b-c-45-1012-1013-a-2-b-c-45-2-1012




Question Number 215255 by Rasheed.Sindhi last updated on 01/Jan/25
a,b,c are pythagorean triples  For the following values:   determinant ((a,b,( c)),(5,(12),(13)))  a^2 =b+c  _(⇒5^2 =12+13=25)    determinant ((a,b,( c)),((45),(1012),(1013)))a^2 =b+c_(       ⇒45^2 =1012+1013=2025)   ⇒45^2 =1012+1013=2025      determinant ((( _   determinant (((HAPPY  NEW  YEAR!)))^   )))
$${a},{b},{c}\:{are}\:{pythagorean}\:{triples} \\ $$$${For}\:{the}\:{following}\:{values}: \\ $$$$\begin{array}{|c|c|}{{a}}&\hline{{b}}&\hline{\:{c}}\\{\mathrm{5}}&\hline{\mathrm{12}}&\hline{\mathrm{13}}\\\hline\end{array}\:\:\underset{\Rightarrow\mathrm{5}^{\mathrm{2}} =\mathrm{12}+\mathrm{13}=\mathrm{25}} {{a}^{\mathrm{2}} ={b}+{c}\:\:} \\ $$$$\begin{array}{|c|c|}{{a}}&\hline{{b}}&\hline{\:{c}}\\{\mathrm{45}}&\hline{\mathrm{1012}}&\hline{\mathrm{1013}}\\\hline\end{array}\underset{\:\:\:\:\:\:\:\Rightarrow\mathrm{45}^{\mathrm{2}} =\mathrm{1012}+\mathrm{1013}=\mathrm{2025}} {{a}^{\mathrm{2}} ={b}+{c}} \\ $$$$\Rightarrow\mathrm{45}^{\mathrm{2}} =\mathrm{1012}+\mathrm{1013}=\mathrm{2025} \\ $$$$\: \\ $$$$\begin{array}{|c|}{\:_{\:} \begin{array}{|c|}{\mathcal{HAPPY}\:\:\mathcal{NEW}\:\:\mathcal{YEAR}!}\\\hline\end{array}^{\:} \:}\\\hline\end{array} \\ $$

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