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Question Number 216592 by Davidtim last updated on 11/Feb/25
if we have the following system:  ((tanx)/(tany))=a  x±y=α  we have the general candition:  −1≤(((a−1)/(a+1)))sinα≤1  if you apply the general candition by  the following system it does not give  us the reality, despite this system have  the solution.  ((tanx)/(tany))=−3  x−y=(π/2)
$${if}\:{we}\:{have}\:{the}\:{following}\:{system}: \\ $$$$\frac{{tanx}}{{tany}}={a} \\ $$$${x}\pm{y}=\alpha \\ $$$${we}\:{have}\:{the}\:{general}\:{candition}: \\ $$$$−\mathrm{1}\leqslant\left(\frac{{a}−\mathrm{1}}{{a}+\mathrm{1}}\right){sin}\alpha\leqslant\mathrm{1} \\ $$$${if}\:{you}\:{apply}\:{the}\:{general}\:{candition}\:{by} \\ $$$${the}\:{following}\:{system}\:{it}\:{does}\:{not}\:{give} \\ $$$${us}\:{the}\:{reality},\:{despite}\:{this}\:{system}\:{have} \\ $$$${the}\:{solution}. \\ $$$$\frac{{tanx}}{{tany}}=−\mathrm{3} \\ $$$${x}−{y}=\frac{\pi}{\mathrm{2}} \\ $$

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