Solve-for-non-negative-integers-n-3-3m-m-2n-1-

Question Number 216664 by Rasheed.Sindhi last updated on 14/Feb/25

$$\mathrm{Solve}\:\mathrm{for}\:\mathrm{non}-\mathrm{negative}\:\mathrm{integers}: \\ $$$$\:\:\:\mathrm{n}^{\mathrm{3}} =\mathrm{3m}\left(\mathrm{m}+\mathrm{2n}+\mathrm{1}\right) \\ $$

Answered by AntonCWX last updated on 15/Feb/25

$${m}={n}=\mathrm{0} \\ $$

Commented by Rasheed.Sindhi last updated on 15/Feb/25

$${process}\:{please}. \\ $$

Commented by AntonCWX08 last updated on 16/Feb/25

$${I}\:{mean}\:{its}\:{obvious}\:{right}? \\ $$$${n}^{\mathrm{3}} =\mathrm{3}{m}\left({n}+\mathrm{2}{m}+\mathrm{1}\right) \\ $$$${Just}\:{multiply}\:{both}\:{by}\:{zero}\:{and}\:{done} \\ $$

Commented by Rasheed.Sindhi last updated on 16/Feb/25

$${Can}\:{you}\:{prove}\:{that}\:{this}\:{is}\:\boldsymbol{{only}} \\ $$$$\boldsymbol{{solution}}? \\ $$

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