Question Number 9342 by FilupSmith last updated on 01/Dec/16 $$\mathrm{Solve}\:\mathrm{for}\:{n} \\ $$$${n}^{\mathrm{2}} \geqslant{n}^{\mathrm{3}} −\mathrm{1} \\ $$ Answered by mrW last updated on 02/Dec/16 $$\mathrm{n}^{\mathrm{3}} −\mathrm{n}^{\mathrm{2}}…
Question Number 140407 by mnjuly1970 last updated on 07/May/21 $$\:\:\:\: \\ $$$$\:\:\:\:{prove}\:{that}\:\langle\:\mathrm{X}:=\mathbb{R}\:,\:\tau_{{e}} \:\rangle\:{is} \\ $$$$\:\:\:\:\:\:{a}\:{second}\:{topology}\:{space}\:. \\ $$$$\:\:\:\:\:\tau_{{e}} \:\:{is}\:\mathscr{E}{uclidian}\:{topology}\:{on}\:\mathbb{R}. \\ $$$$\:\:\:\mathrm{H}{int}\:::\:\:\mathcal{B}=\:\left\{\:\left({r}−\frac{\mathrm{1}}{{n}}\:,{r}+\frac{\mathrm{1}}{{n}}\right)\mid\:{r}\in\mathrm{Q}\:,\:{n}\in\mathbb{N}\right\} \\ $$$$\:\:\:{is}\:\:{a}\:{base}\:{for}\:\tau_{{e}\:} ….. \\ $$…
Question Number 9324 by uchechukwu okorie favour last updated on 30/Nov/16 $${if}\:\:{x}=\frac{{a}\left(\mathrm{1}−{r}^{{n}} \right)}{\mathrm{1}−{r}}\:{make}\:{r}\:{the}\: \\ $$$${subject}\:{of}\:{the}\:{formula} \\ $$ Answered by mrW last updated on 30/Nov/16 $$\mathrm{let}\:\mathrm{k}=\frac{\mathrm{x}}{\mathrm{a}}…
Question Number 140392 by mathdanisur last updated on 07/May/21 $${let}\:{f}:\left[\mathrm{0};\mathrm{1}\right]\rightarrow\mathbb{R},\:{prove}\:{that}\:\exists{x}_{\mathrm{0}} ,{x}_{\mathrm{1}} ,{x}_{\mathrm{2}} \in\left(\mathrm{0};\mathrm{1}\right) \\ $$$${such}\:{that}\:\:\frac{{f}\left({x}_{\mathrm{0}} \right)}{{x}_{\mathrm{0}} ^{\mathrm{2}} }+\frac{{f}\left({x}_{\mathrm{1}} \right)}{\mathrm{2}{x}_{\mathrm{1}} ^{\mathrm{2}} }=\mathrm{3}{f}\left({x}_{\mathrm{2}} \right) \\ $$ Terms…
Question Number 9323 by uchechukwu okorie favour last updated on 30/Nov/16 $${if}\:\:{x}=\frac{{a}\left(\mathrm{1}−{r}^{{n}} \right)}{\mathrm{1}−{r}}\:{make}\:{r}\:{the}\: \\ $$$${subject}\:{of}\:{the}\:{formula} \\ $$ Commented by geovane10math last updated on 30/Nov/16 $${x}\:=\:\frac{{a}\left(−{r}^{{n}}…
Question Number 9312 by tawakalitu last updated on 29/Nov/16 $$\mathrm{Solve}\:\mathrm{simultaneously} \\ $$$$\mathrm{xy}\:+\:\mathrm{x}\:+\:\mathrm{y}\:=\:\mathrm{23}\:\:\:\:…….\:\left(\mathrm{i}\right) \\ $$$$\mathrm{xz}\:+\:\mathrm{x}\:+\:\mathrm{z}\:=\:\mathrm{41}\:\:\:\:……..\:\left(\mathrm{ii}\right) \\ $$$$\mathrm{yz}\:+\:\mathrm{y}\:+\:\mathrm{z}\:=\:\mathrm{27}\:\:\:\:\:……..\:\left(\mathrm{iii}\right) \\ $$ Commented by RasheedSoomro last updated on 30/Nov/16…
Question Number 9278 by j.masanja06@gmail.com last updated on 28/Nov/16 $$\mathrm{represent}\:\mathrm{in}\:\mathrm{sigma}\:\mathrm{notation}\: \\ $$$$−\mathrm{1}+\mathrm{4}−\mathrm{9}+\mathrm{16}……………… \\ $$ Commented by FilupSmith last updated on 28/Nov/16 $$=\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\left(−\mathrm{1}\right)^{{n}} {n}^{\mathrm{2}}…
Question Number 9279 by j.masanja06@gmail.com last updated on 28/Nov/16 $$\mathrm{evalute}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\: \\ $$$$\overset{\mathrm{5}} {\sum}_{\mathrm{m}=\mathrm{2}\:} \mathrm{m}^{\mathrm{4}} \\ $$ Answered by mrW last updated on 28/Nov/16 $$\mathrm{please}\:\mathrm{refer}\:\mathrm{to}\:\mathrm{Q9232}\:\mathrm{and}\:\mathrm{Q9265}. \\…
Question Number 140346 by mathsuji last updated on 06/May/21 $${if},\:{x}>\mathrm{4}\:;\:\mathrm{5}!\centerdot{x}!={z}!\:;\:{find}:\:{x}+{z}=? \\ $$ Answered by hknkrc46 last updated on 06/May/21 $$\mathrm{5}!\:=\:\frac{\boldsymbol{{z}}!}{\boldsymbol{{x}}!}\:\Rightarrow\:\begin{cases}{\boldsymbol{{x}}\:=\:\mathrm{5}!\:−\:\mathrm{1}\:\Rightarrow\:\boldsymbol{{z}}\:=\:\mathrm{120}}\\{\boldsymbol{{x}}\:+\:\boldsymbol{{z}}\:=\:\mathrm{119}\:+\:\mathrm{120}\:=\:\mathrm{239}}\end{cases} \\ $$ Commented by mathsuji…
Question Number 74801 by behi83417@gmail.com last updated on 30/Nov/19 $$\begin{cases}{\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\boldsymbol{\mathrm{y}}^{\mathrm{3}} =\mathrm{23}}\\{\boldsymbol{\mathrm{x}}^{\mathrm{3}} +\boldsymbol{\mathrm{y}}^{\mathrm{2}} =\mathrm{32}}\end{cases}\:\:\:\:\:\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{for}}\:\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{y}}\:. \\ $$ Commented by MJS last updated on 30/Nov/19 $$\mathrm{if}\:\mathrm{you}\:\mathrm{plot}\:\mathrm{these}\:\mathrm{you}\:\mathrm{see}\:\mathrm{there}'\mathrm{s}\:\mathrm{only}\:\mathrm{one} \\…