Question Number 139978 by mathdanisur last updated on 02/May/21 $$\underset{\:−\mathrm{1}} {\overset{\:\mathrm{5}} {\int}}\left(\frac{\mathrm{1}}{\mathrm{2}}{x}−\mathrm{2}\right)\centerdot\mathrm{5}^{\boldsymbol{{x}}^{\mathrm{2}} −\mathrm{4}\boldsymbol{{x}}−\mathrm{5}} \:{dx}=? \\ $$ Answered by MJS_new last updated on 03/May/21 $$\int\left(\frac{\mathrm{1}}{\mathrm{2}}{x}−\mathrm{2}\right)\mathrm{5}^{{x}^{\mathrm{2}} −\mathrm{4}{x}−\mathrm{5}}…
Question Number 8905 by j.masanja06@gmail.com last updated on 04/Nov/16 $$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x} \\ $$$$\mathrm{3}^{\mathrm{x}} \:=\mathrm{9x} \\ $$ Answered by Rasheed Soomro last updated on 04/Nov/16 $$\mathrm{3}^{\mathrm{x}} \:=\mathrm{9x}\Rightarrow\mathrm{x}=\mathrm{3}^{\mathrm{x}−\mathrm{2}}…
Question Number 8885 by tawakalitu last updated on 03/Nov/16 $$\mathrm{Solve}\:\mathrm{simultaneously} \\ $$$$ \\ $$$$\mathrm{2x}\:+\:\mathrm{y}\:−\:\mathrm{2z}\:=\:\mathrm{0}\:………\:\left(\mathrm{i}\right) \\ $$$$\mathrm{7x}\:+\:\mathrm{6y}\:−\:\mathrm{9z}\:=\:\mathrm{0}\:…….\:\left(\mathrm{ii}\right) \\ $$$$\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{y}^{\mathrm{3}} \:+\:\mathrm{z}^{\mathrm{3}} \:=\:\mathrm{1728}\:\:\:\:……\:\left(\mathrm{iii}\right) \\ $$ Answered by…
Question Number 139948 by qaz last updated on 02/May/21 $${If}\:\:\:\:{x}^{\mathrm{2}} +{xy}+{y}^{\mathrm{2}} =\mathrm{0} \\ $$$${find}\:::\:\:\:\left(\frac{{x}}{{x}+{y}}\right)^{\mathrm{2023}} +\left(\frac{{y}}{{x}+{y}}\right)^{\mathrm{2023}} \\ $$ Answered by Rasheed.Sindhi last updated on 04/May/21 $$\frac{{x}}{{y}}+\frac{{y}}{{x}}=−\mathrm{1}\Rightarrow\frac{{y}}{{x}}=−\left(\mathrm{1}+\frac{{x}}{{y}}\right)…
Question Number 8877 by tawakalitu last updated on 03/Nov/16 Commented by Rasheed Soomro last updated on 03/Nov/16 $$\mathrm{Not}\:\mathrm{related}\:\mathrm{to}\:\mathrm{this}\:\mathrm{question}. \\ $$$$\mathrm{Please}\:\mathrm{see}\:\mathrm{my}\:\mathrm{answers}\:\mathrm{to}\:\mathrm{your} \\ $$$$\mathrm{question}\:#\mathrm{8847}\:\:\:\mathrm{and}\:\mathrm{confirm} \\ $$$$\mathrm{whether}\:\mathrm{the}\:\mathrm{answer}\:\mathrm{is}\:\mathrm{correct} \\…
Question Number 74412 by ajfour last updated on 24/Nov/19 $${a},{b},{c}\:{are}\:{given}\:{real}\:{constants}. \\ $$$${p},{q},{r},{t}\:{are}\:{unknowns}\:{from}\:{which} \\ $$$${we}\:{can}\:{choose}\:{values}\:{of}\:{two}\:{of} \\ $$$${them}\:\left({non}\:{zero}\right)\:{and}\:{have}\:{to}\: \\ $$$${determine}\:{the}\:{other}\:{two}\:\left({non}\:{zero}\right), \\ $$$${obeying}\:\:{two}\:{equations}\:{given}\:{below} \\ $$$$\:{p}^{\mathrm{2}} +{q}\left(\mathrm{1}+{bq}\right){t}^{\mathrm{2}} +{q}\left({ap}+{br}\right){t} \\…
Question Number 8873 by j.masanja06@gmail.com last updated on 03/Nov/16 $$\mathrm{simplify}\:\mathrm{5y}^{\mathrm{2}} \:×\:\mathrm{6x}^{\mathrm{4}} \\ $$ Answered by FilupSmith last updated on 03/Nov/16 $$\mathrm{5}{y}^{\mathrm{2}} ×\mathrm{6}{x}^{\mathrm{4}} =\mathrm{30}{y}^{\mathrm{2}} {x}^{\mathrm{4}} \\…
Question Number 139940 by mathdanisur last updated on 02/May/21 $${There}\:{are}\:\mathrm{4}\:{children}\:{in}\:{the}\:{team}. \\ $$$${Find}\:{the}\:{probability}\:{that}\:{three}\:{are} \\ $$$${girls}\:{and}\:{one}\:{is}\:{a}\:{boy}. \\ $$ Answered by mr W last updated on 02/May/21 $${children}\:{are}\:{different}:…
Question Number 139943 by mathsuji last updated on 02/May/21 $${The}\:{train}\:{is}\:{moving}\:{at}\:{a}\:{speed}\:{of}\:\mathrm{12}\:{m}/{san}. \\ $$$${In}\:{this}\:{cose},\:{it}\:{seems}\:{to}\:{the}\:{passenger} \\ $$$${in}\:{the}\:{car}\:{that}\:{the}\:{direction}\:{of}\:{the} \\ $$$${raindrops}\:{is}\:{at}\:{an}\:{angle}\:{of}\:\mathrm{30}\:{degrees} \\ $$$${to}\:{the}\:{vertical}.\:{Find}\:{the}\:\:{average} \\ $$$${speed}\:{of}\:{raindrops}. \\ $$ Terms of Service…
Question Number 139936 by Snail last updated on 02/May/21 $${Find}\:{all}\:{integers}\:{x}\:{and}\:{y}\:{i}.{e}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{9999}\left({x}−{y}\right) \\ $$ Answered by Rasheed.Sindhi last updated on 04/May/21 $$\left({x}+{y}\right)^{\mathrm{2}} =\mathrm{9999}\left({x}−{y}\right)+\mathrm{2}{xy} \\ $$$$\left({x}−{y}\right)^{\mathrm{2}}…