Question Number 170914 by mathlove last updated on 03/Jun/22 Commented by infinityaction last updated on 03/Jun/22 $${x}\:=\:\:\frac{\mathrm{1}}{\:^{\mathrm{3}} \sqrt{\mathrm{2}}\:−\mathrm{1}}\:\:\:\:\:\:\:{g}.{p}.\:{sum} \\ $$$$\mathrm{1}+\frac{\mathrm{1}}{{x}}\:=\:^{\mathrm{3}} \sqrt{\mathrm{2}\:} \\ $$$$\left(\mathrm{1}+\frac{\mathrm{1}}{{x}}\right)^{\mathrm{3}} \:=\:\mathrm{2} \\…
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Question Number 105018 by bemath last updated on 25/Jul/20 $$\frac{\sqrt{\sqrt{\mathrm{5}}+\mathrm{2}}\:+\:\sqrt{\sqrt{\mathrm{5}}−\mathrm{2}}}{\:\sqrt{\sqrt{\mathrm{5}}+\mathrm{1}}}\:? \\ $$ Commented by bemath last updated on 25/Jul/20 $${thank}\:{you}\:{all} \\ $$ Answered by som(math1967)…
Question Number 170520 by mr W last updated on 25/May/22 $${solve}\:{for}\:{x} \\ $$$$\left(\mathrm{1}+\frac{\mathrm{1}}{{x}}\right)^{{x}+\mathrm{1}} =\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{10}}\right)^{\mathrm{10}} \\ $$ Commented by mr W last updated on 26/May/22 $${yes}.\:{show}\:{how}\:{you}\:{got}?…
Question Number 104821 by bobhans last updated on 24/Jul/20 $$\mathrm{3}+\mathrm{8}+\mathrm{15}+\mathrm{24}+\mathrm{35}+…\: \\ $$$${find}\:{sum}\:{of}\:\mathrm{50}^{{th}} −{term}\: \\ $$ Answered by bemath last updated on 24/Jul/20 $${S}_{\mathrm{50}} \:=\:\mathrm{3}{C}_{\mathrm{1}} ^{\:\mathrm{50}}…
Question Number 170270 by cortano1 last updated on 19/May/22 Commented by cortano1 last updated on 19/May/22 $$\:{Find}\:\alpha\: \\ $$ Commented by mr W last updated…
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Question Number 39058 by jasno91 last updated on 02/Jul/18 Commented by maxmathsup by imad last updated on 25/Jul/18 $${if}\:{you}\:{want}\:{developpement}\:{let} \\ $$$${A}\left({x}\right)=\left(\mathrm{5}{x}−\mathrm{3}\right)\left({x}+\mathrm{4}\right)−\left(\mathrm{2}{x}+\mathrm{5}\right)\left(\mathrm{3}{x}−\mathrm{4}\right) \\ $$$${A}\left({x}\right)=\mathrm{5}{x}^{\mathrm{2}} \:+\mathrm{20}{x}\:−\mathrm{3}{x}\:−\mathrm{12}\:−\left(\mathrm{6}{x}^{\mathrm{2}} \:−\mathrm{8}{x}\:+\mathrm{15}{x}\:−\mathrm{20}\right)…
Question Number 104571 by ajfour last updated on 22/Jul/20 $$\frac{\mathrm{1}}{\mathrm{8}}\:\boldsymbol{\div}\:\frac{\mathrm{1}}{\mathrm{8}}\:\boldsymbol{\div}\:\frac{\mathrm{1}}{\mathrm{8}}\:\boldsymbol{\div}\:\frac{\mathrm{1}}{\mathrm{8}}\:=\:? \\ $$ Answered by OlafThorendsen last updated on 22/Jul/20 $$=\:\left(\frac{\mathrm{1}}{\mathrm{8}}\:\boldsymbol{\div}\:\frac{\mathrm{1}}{\mathrm{8}}\right)\:\boldsymbol{\div}\left(\:\frac{\mathrm{1}}{\mathrm{8}}\:\boldsymbol{\div}\:\frac{\mathrm{1}}{\mathrm{8}}\right) \\ $$$$=\:\left(\mathrm{1}\right)\:\boldsymbol{\div}\left(\:\mathrm{1}\right) \\ $$$$=\:\mathrm{1} \\…