Question Number 206912 by BaliramKumar last updated on 30/Apr/24 Answered by A5T last updated on 30/Apr/24 $${cos}^{\mathrm{2}} \theta+\mathrm{3}\left(\mathrm{1}−{cos}^{\mathrm{2}} \theta\right)+\mathrm{2}=\mathrm{5}−\mathrm{2}{cos}^{\mathrm{2}} \theta \\ $$$$\Rightarrow{Max}=\mathrm{5}−\mathrm{0};\:{Min}=\mathrm{5}−\mathrm{2}\Rightarrow{Difference}=\mathrm{2} \\ $$ Answered…
Question Number 205922 by cortano12 last updated on 03/Apr/24 $$\:\:\:{x}\:=\:\mathrm{2}\:\left({mod}\:\mathrm{7}\right) \\ $$$$\:\:\:{x}=\mathrm{3}\:\left({mod}\:\mathrm{4}\right) \\ $$$$\:\:\:{x}=? \\ $$ Answered by Rasheed.Sindhi last updated on 03/Apr/24 $$\:\:\:{x}\:=\:\mathrm{2}\:\left({mod}\:\mathrm{7}\right)\:\wedge\:{x}=\mathrm{3}\:\left({mod}\:\mathrm{4}\right) \\…
Question Number 204568 by pticantor last updated on 21/Feb/24 $$\boldsymbol{{how}}\:\boldsymbol{{to}}\:\boldsymbol{{convert}}\:\mathrm{31230}\:\boldsymbol{{in}}\:\boldsymbol{{base}}\:\mathrm{60}? \\ $$$$\boldsymbol{{pls}}\:\boldsymbol{{help}} \\ $$ Answered by A5T last updated on 22/Feb/24 $$\mathrm{31230}=\mathrm{520}×\mathrm{60}+\mathrm{30}=\left(\mathrm{8}×\mathrm{60}+\mathrm{40}\right)×\mathrm{60}+\mathrm{30} \\ $$$$=\mathrm{8}×\mathrm{60}^{\mathrm{2}} +\mathrm{40}×\mathrm{60}+\mathrm{30}=\mathrm{8}{eU}_{\mathrm{60}}…
Question Number 203509 by Fridunatjan08 last updated on 20/Jan/24 $${Find}\:{the}\:{value}\:{of}: \\ $$$$\underset{{n}=\mathrm{1}} {\overset{\infty} {\prod}}\frac{\mathrm{2}^{{n}} +\mathrm{1}}{\mathrm{2}^{{n}} −\mathrm{1}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 203146 by Rasheed.Sindhi last updated on 11/Jan/24 $$\mathcal{D}{etermine}\:\overline {{ab}}\:\left({a}>{b}\right)\:{such}\:{that}\left(\:\overline {{ab}}+\overline {{ba}}\right)\: \\ $$$${and}\:\left(\overline {{ab}}−\overline {{ba}}\right)\:{are}\:{both}\:{perfect}\:{squares}. \\ $$ Answered by Frix last updated on…
Question Number 202716 by Rasheed.Sindhi last updated on 01/Jan/24 $$\overline {\:\:{abcd}\:\:}{is}\:{a}\:{four}\:{digit}\:{number} \\ $$$${such}\:{that}\:{a}^{\mathrm{2}} +{b}^{\mathrm{2}} +{c}^{\mathrm{2}} +{d}^{\mathrm{2}} =\overline {\:{cd}\:} \\ $$$${and}\:\overline {\:{cd}\:}−\overline {\:{d}\:}=\overline {\:{ab}\:}. \\ $$$$\mathcal{F}{ind}\:{the}\:{number}.…
Question Number 201418 by cortano12 last updated on 06/Dec/23 $$\:\:\:\:\:\:\mathrm{2025}^{\mathrm{2025}} \:=\:\mathrm{x}\:\left(\mathrm{mod}\:\mathrm{17}\:\right) \\ $$ Answered by mr W last updated on 06/Dec/23 $$\mathrm{2025}^{\mathrm{2025}} \:\left({mod}\:\mathrm{17}\right) \\ $$$$=\left(\mathrm{119}×\mathrm{17}+\mathrm{2}\right)^{\mathrm{2025}}…
Question Number 201352 by cortano12 last updated on 05/Dec/23 $$\:\:\:\mathrm{2023}^{\mathrm{2023}} \:=\:…\:\left(\mathrm{mod}\:\mathrm{13}\right) \\ $$ Answered by Rasheed.Sindhi last updated on 05/Dec/23 $$\:\:\:\mathrm{2023}^{\mathrm{2023}} \:\equiv\:…\:\left(\mathrm{mod}\:\mathrm{13}\right) \\ $$$$\mathrm{2023}^{\mathrm{2023}} \\…
Question Number 200836 by Rasheed.Sindhi last updated on 24/Nov/23 $$ \\ $$$$\mathcal{L}{et}\overline {\:{abc}\:}+\overline {\:{bca}\:}+\overline {\:{cab}\:}=\overline {\:{defg}\:} \\ $$$${where}\:{a},{b},…,{g}\:{are}\:{decimal}\:{digits} \\ $$$$\left({may}\:{be}\:{equal}\:{to}\:\mathrm{0}\right)\: \\ $$$${Show}\:{that} \\ $$$$\left({i}\right)\overline {\:{dg}\:}={a}+{b}+{c}…
Question Number 200834 by Rasheed.Sindhi last updated on 24/Nov/23 $${Show}\:{that}\:\:\:\overline {\:\:{abc}\:}+\overline {\:{bca}\:}+\overline {\:{cab}\:} \\ $$$${is}\:{divisible}\:{by}\:\mathrm{37} \\ $$ Answered by AST last updated on 24/Nov/23 $$\mathrm{111}\left({a}+{b}+{c}\right)\:{is}\:{a}\:{multiple}\:{of}\:\mathrm{37}…