Question Number 176549 by doline last updated on 21/Sep/22 $${donner}\:{la}\:{forme}\:{trigonometrique}\:{de}\:\mathrm{1}/\mathrm{4}\left({cos}\Pi/\mathrm{9}+{isin}\Pi/\mathrm{9}\right) \\ $$ Answered by Ar Brandon last updated on 21/Sep/22 $$\frac{\mathrm{1}}{\mathrm{4}\left(\mathrm{cos}\frac{\pi}{\mathrm{9}}+{i}\mathrm{sin}\frac{\pi}{\mathrm{9}}\right)}=\frac{\mathrm{1}}{\mathrm{4}{e}^{\frac{\pi}{\mathrm{9}}{i}} }=\frac{\mathrm{1}}{\mathrm{4}}{e}^{−\frac{\pi}{\mathrm{9}}{i}} \\ $$$$=\frac{\mathrm{1}}{\mathrm{4}}\left(\mathrm{cos}\frac{\pi}{\mathrm{9}}−{i}\mathrm{sin}\frac{\pi}{\mathrm{9}}\right) \\…
Question Number 176379 by doline last updated on 17/Sep/22 $${lineariser}\:{sin}^{\mathrm{5}} \left({x}\right) \\ $$ Answered by a.lgnaoui last updated on 17/Sep/22 $$\mathrm{sin}\:^{\mathrm{5}} \left({x}\right)=\left(\frac{{e}^{{ix}} −{e}^{−{ix}} }{\mathrm{2}}\right)^{\mathrm{5}} \\…
Question Number 176366 by doline last updated on 17/Sep/22 $${donner}\:{la}\:{forme}\:{trigonometrique}\:{de}\left(\mathrm{1}−{i}\sqrt{}\mathrm{3}\right)\left(\mathrm{1}+{i}\right)\left({cos}\theta−{isin}\theta\right) \\ $$ Answered by Ar Brandon last updated on 17/Sep/22 $$\left(\mathrm{2}{e}^{−\frac{\pi}{\mathrm{3}}{i}} \right)\left(\sqrt{\mathrm{2}}{e}^{\frac{\pi}{\mathrm{4}}{i}} \right)\left({e}^{−{i}\theta} \right)=\mathrm{2}\sqrt{\mathrm{2}}{e}^{\left(−\frac{\pi}{\mathrm{3}}+\frac{\pi}{\mathrm{4}}−\theta\right){i}} \\…
Question Number 176123 by doline last updated on 12/Sep/22 $$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 176118 by doline last updated on 12/Sep/22 $$ \\ $$ Commented by Rasheed.Sindhi last updated on 13/Sep/22 $$\mathcal{S}{pace}\:{booked}\:{for}\:{future}\:{question}? \\ $$ Terms of Service…
Question Number 176090 by doline last updated on 11/Sep/22 $${determiner}\:{z}\:{tel}\:{que}\:{z}={z}^{\mathrm{2}} −{z}+\mathrm{2} \\ $$$$ \\ $$ Commented by Frix last updated on 12/Sep/22 $$\mathrm{why}\:\mathrm{not}\:\mathrm{simply}\:\mathrm{use} \\ $$$${z}^{\mathrm{2}}…
Question Number 176070 by doline last updated on 11/Sep/22 $${demontrer}\:{par}\:{recurrence}\:{que}\:{pour}\:{tout}\:{n}>\mathrm{0}\:{appartenent}\:{a}\:{l}\:{ensemble}\:{des}\:{entier}\:{naturel}\:\mathrm{3}^{\mathrm{2}{n}−\mathrm{2}^{{n}\:} } {est}\:{multiple}\:{de}\:\mathrm{7} \\ $$ Commented by som(math1967) last updated on 11/Sep/22 $$\mathrm{3}^{\mathrm{2}{n}} −\mathrm{2}^{{n}} \\ $$$${p}\left(\mathrm{1}\right)=\mathrm{3}^{\mathrm{2}}…
Question Number 176060 by doline last updated on 11/Sep/22 $${x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{5}=\mathrm{0} \\ $$ Answered by Ar Brandon last updated on 11/Sep/22 $${x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{5}=\mathrm{0}\:\Rightarrow\left({x}−\mathrm{2}\right)^{\mathrm{2}} +\mathrm{1}=\mathrm{0} \\…
Question Number 176049 by doline last updated on 11/Sep/22 $${calculer}\:\left(−\mathrm{1}/\mathrm{2}+{i}\sqrt{\left.\mathrm{3}/\mathrm{2}\right)^{\mathrm{3}} }\right. \\ $$ Answered by Rasheed.Sindhi last updated on 11/Sep/22 $$−\mathrm{1}/\mathrm{2}+{i}\sqrt{\left.\mathrm{3}/\mathrm{2}\right)^{\mathrm{3}} } \\ $$$$=−\frac{\mathrm{1}}{\mathrm{2}}+\mathrm{i}\left(\sqrt{\mathrm{3}/\mathrm{2}}\:\right)^{\mathrm{3}} \\…
Question Number 109888 by bagusadisaputra last updated on 26/Aug/20 $$\mathrm{2}^{{x}+\mathrm{5}} =\sqrt{\mathrm{8}^{{x}} } \\ $$ Answered by som(math1967) last updated on 26/Aug/20 $$\mathrm{2}^{\mathrm{x}+\mathrm{5}} =\left(\mathrm{2}^{\mathrm{3x}} \right)^{\frac{\mathrm{1}}{\mathrm{2}}} \\…