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Question-220495

Question Number 220495 by Jubr last updated on 13/May/25 Commented by mr W last updated on 14/May/25 $${i}\:{guess}\:{even}\:{you}\:{also}\:{don}'{t}\:{know} \\ $$$${what}\:{the}\:{question}\:{means}\:{with}\:{all} \\ $$$${the}\:{arrows}.\:{when}\:{the}\:{question}\:{is} \\ $$$${unclear},\:{it}\:{can}\:{not}\:{be}\:{solved}.\:{so} \\…

Question-220340

Question Number 220340 by Noorzai last updated on 11/May/25 Answered by som(math1967) last updated on 11/May/25 $$\:{b}^{\mathrm{2}} {a}−{a}^{\mathrm{2}} {b}+{c}^{\mathrm{2}} {b}−{c}^{\mathrm{2}} {a}+{b}^{\mathrm{2}} {c}−{a}^{\mathrm{2}} {c} \\ $$$$={ba}\left({b}−{a}\right)+{c}^{\mathrm{2}}…

Question-220007

Question Number 220007 by Noorzai last updated on 04/May/25 Commented by MrGaster last updated on 04/May/25 conditions are not enough and the meaning is unclear, please add or upload again if there is anything that has not been added. Answered by efronzo1 last updated on 04/May/25 $$\:{a}^{\mathrm{3}}…

let-s-gt-1-be-a-real-number-for-all-continues-function-f-0-1-R-such-that-0-1-f-x-0-determind-of-the-exist-a-positive-constant-K-s-statisfying-0-1-f-x-Li-s-x-dx

Question Number 219988 by Nicholas666 last updated on 04/May/25 $$ \\ $$$$\:\:\:\:\mathrm{let}\:{s}>\mathrm{1}\:\mathrm{be}\:\mathrm{a}\:\mathrm{real}\:\mathrm{number}.\:\mathrm{for}\:\mathrm{all}\:\mathrm{continues}\:\mathrm{function}\:{f}:\left[\mathrm{0},\mathrm{1}\right]\rightarrow\mathbb{R} \\ $$$$\:\:\:\mathrm{such}\:\mathrm{that}\:\int_{\:\mathrm{0}} ^{\:\mathrm{1}} {f}\left({x}\right)=\mathrm{0},\:\mathrm{determind}\:\mathrm{of}\:\mathrm{the}\:\mathrm{exist}\:\mathrm{a} \\ $$$$\:\:\:\:\:\mathrm{positive}\:\mathrm{constant}\:{K}\left({s}\right)\:\mathrm{statisfying}: \\ $$$$\:\:\:\left(\int_{\mathrm{0}} ^{\:\mathrm{1}} {f}\left({x}\right)\centerdot\mathrm{Li}_{{s}} \left({x}\right){dx}\right)^{\mathrm{2}} \geqslant{K}\left({s}\right)\int_{\:\mathrm{0}} ^{\:\mathrm{1}}…

Question-220034

Question Number 220034 by Tawa11 last updated on 04/May/25 Answered by efronzo1 last updated on 04/May/25 $$\:\left(\mathrm{1}\right)\:\mathrm{x}^{\mathrm{2}} \:=\:\mathrm{96}{a} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{y}^{\mathrm{2}} \:=\:\mathrm{96}{b} \\ $$$$\:\left(\mathrm{3}\right)\:{a}+{b}\:=\:\mathrm{96}\Rightarrow{b}=\:\mathrm{96}−{a} \\ $$$$\:\Rightarrow\:\mathrm{36}^{\mathrm{2}}…