Question Number 82591 by Learner-123 last updated on 22/Feb/20 $${A}\:{closed}\:{surface}\:{is}\:{defined}\:{in}\:{spherical} \\ $$$${coordinates}\:{by}\:\mathrm{3}<{r}<\mathrm{5}\:,\:\mathrm{0}.\mathrm{1}\pi<\theta<\mathrm{0}.\mathrm{3}\pi, \\ $$$$\mathrm{1}.\mathrm{2}\pi<\phi<\mathrm{1}.\mathrm{6}\pi.\:\boldsymbol{{F}}{ind}\:{the}\:{total}\:{surface} \\ $$$${area}. \\ $$ Commented by Learner-123 last updated on 22/Feb/20…
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