Question Number 52457 by Necxx last updated on 07/Jan/19 $${Two}\:{radioactive}\:{elements}\:{A}\:{and}\:{B} \\ $$$${has}\:{half}\:{lives}\:{of}\:\mathrm{100}\:{and}\:\mathrm{50}{years}. \\ $$$${Samples}\:{of}\:{A}\:{and}\:{B}\:{initial}\:{contains} \\ $$$${equal}\:{numbers}\:{of}\:{atoms}.{What}\:{is} \\ $$$${the}\:{ratio}\:{of}\:{the}\:{remaining}\:{atoms} \\ $$$${of}\:{A}\:{to}\:{that}\:{of}\:{B}\:{after}\:\mathrm{200}{years}? \\ $$ Answered by MJS…
Question Number 116078 by Study last updated on 30/Sep/20 $${prove}\:{that}\:\:\:{Fr}=\frac{{v}^{\mathrm{2}} }{{gh}}\:\:\:\:{froude}\:{numer} \\ $$ Answered by MrGaster last updated on 06/Jan/25 $${F}_{{r}} =\frac{{v}^{\mathrm{2}} }{{gh}}\left({froude}\:{numer}\right) \\ $$$$\mathrm{Let}\:{v}\:\mathrm{be}\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{the}\:\mathrm{object},{g}\:\mathrm{be}\:\mathrm{the}\:\mathrm{acceleration}\:\mathrm{due}\:\mathrm{to}\:\mathrm{gravity},\mathrm{and}\:{h}\:\mathrm{be}\:\mathrm{the}\:\mathrm{characteristic}\:\mathrm{length}…
Question Number 116079 by Study last updated on 30/Sep/20 $${prove}\:{that}\:{Re}=\frac{\rho\centerdot{v}\centerdot{d}}{\mu}\:\:\:\:\:{renulds}\:{number} \\ $$ Answered by Olaf last updated on 01/Oct/20 $$\mathrm{It}\:\mathrm{suffices}\:\mathrm{to}\:\mathrm{resize}\:\mathrm{the}\:\mathrm{Navier}−\mathrm{Stokes} \\ $$$$\mathrm{equations}.\:\mathrm{The}\:\mathrm{dimensionless}\:\mathrm{factor} \\ $$$$\frac{\rho{vd}}{\mu}\:\mathrm{appears}\:\mathrm{naturally}.\:\mathrm{This}\:\mathrm{is}\:\mathrm{the} \\…
Question Number 181253 by sciencestudent last updated on 23/Nov/22 $${define}\:{microscopic}\:{and}\:{macroscopic} \\ $$$${with}\:{one}\:{one}\:{example}. \\ $$ Commented by sciencestudent last updated on 24/Nov/22 $${no}\:{one}\:{ans}\:{without}\:{i}\:{have}\:{to}\:{request}\:{you} \\ $$$${please}\:{ans}\:{me}! \\…
Question Number 113829 by Study last updated on 15/Sep/20 $${what}\:{is}\:{the}\:{darcy}\:{formula}\:{for} \\ $$$${laminar}\:{flow}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 45748 by rahul 19 last updated on 16/Oct/18 Commented by rahul 19 last updated on 16/Oct/18 $${Ans}.\:\rightarrow\:\left({b}\right). \\ $$ Terms of Service Privacy…
Question Number 45747 by rahul 19 last updated on 16/Oct/18 Answered by ajfour last updated on 16/Oct/18 $$\bar {{p}}_{\mathrm{1}{cm}} =\:{m}\left(\frac{\bar {{p}}_{\mathrm{1}} +\bar {{p}}_{\mathrm{2}} }{\mathrm{2}{m}}−\frac{\bar {{p}}_{\mathrm{1}}…
Question Number 45746 by rahul 19 last updated on 16/Oct/18 Commented by rahul 19 last updated on 16/Oct/18 $${Ans}.\:{is}\:\left({c}\right)\:! \\ $$$${Why}\:\left({a}\right),\left({b}\right)\:{are}\:{wrong}? \\ $$ Terms of…
Question Number 45646 by rahul 19 last updated on 15/Oct/18 $${According}\:{to}\:{relativistic}\:{theory}, \\ $$$${E}^{\mathrm{2}} =\:{p}^{\mathrm{2}} {c}^{\mathrm{2}} +{m}_{\mathrm{0}} ^{\mathrm{2}} {c}^{\mathrm{4}} \:{where}\:{m}_{\mathrm{0}} \:{is}\:{rest}\:{mass}. \\ $$$${For}\:{photon}\:{E}=\:{pc}… \\ $$$$\left({m}_{\mathrm{0}} =\mathrm{0}\:{for}\:{photon}\right)…
Question Number 45539 by rahul 19 last updated on 14/Oct/18 Commented by rahul 19 last updated on 14/Oct/18 $${Ans}:\:\frac{{I}\pi{R}^{\mathrm{2}} }{{c}}\:{where}\:{c}={speed}\:{of}\:{light}. \\ $$ Commented by tanmay.chaudhury50@gmail.com…