Question Number 17255 by Arnab Maiti last updated on 02/Jul/17 | ||
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$$\int_{\mathrm{0}} ^{\:\frac{\Pi}{\mathrm{2}}} \:\frac{\mathrm{d}\left(\mathrm{sinx}+\mathrm{cosx}\right)}{\mathrm{sinx}+\mathrm{cosx}} \\ $$ | ||
Answered by prakash jain last updated on 02/Jul/17 | ||
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$$\mathrm{ln}\:\left(\mathrm{sin}\:{x}+\mathrm{cos}\:{x}\right)\mid_{\mathrm{0}} ^{\pi/\mathrm{2}} =\mathrm{ln}\:\mathrm{1}−\mathrm{ln}\:\mathrm{1}=\mathrm{0} \\ $$ | ||
Commented byArnab Maiti last updated on 02/Jul/17 | ||
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$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{sir}. \\ $$ | ||