Question Number 48837 by ggny last updated on 29/Nov/18
$$\mathrm{0}.\mathrm{25}\left(×+\mathrm{2}\right)=\mathrm{0}.\mathrm{5}\left(\mathrm{2}×−\mathrm{1}\right) \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 29/Nov/18
$${i}\:{think}\:×\:{represent}\:{x}\: \\ $$ $$\mathrm{0}.\mathrm{25}\left({x}+\mathrm{2}\right)=\mathrm{0}.\mathrm{50}\left(\mathrm{2}{x}−\mathrm{1}\right) \\ $$ $${x}+\mathrm{2}=\mathrm{2}\left(\mathrm{2}{x}−\mathrm{1}\right) \\ $$ $${x}+\mathrm{2}=\mathrm{4}{x}−\mathrm{2} \\ $$ $${x}−\mathrm{4}{x}=−\mathrm{2}−\mathrm{2} \\ $$ $$−\mathrm{3}{x}=−\mathrm{4} \\ $$ $${x}=\frac{\mathrm{4}}{\mathrm{3}} \\ $$