Integration Questions

Question Number 62937 by Prithwish sen last updated on 27/Jun/19

$$\int_{\mathrm{0}} ^{\:\:\mathrm{x}} \frac{\mathrm{1}}{\mathrm{1}+\mathrm{x}^{\mathrm{2}} }\:\mathrm{dx} \\$$

Commented bymathmax by abdo last updated on 27/Jun/19

$$\int_{\mathrm{0}} ^{{x}} \:\:\frac{{dt}}{\mathrm{1}+{t}^{\mathrm{2}} }\:=\left[{arctan}\left({t}\right)\right]_{\mathrm{0}} ^{{x}} \:={arctanx}\:. \\$$

Commented byPrithwish sen last updated on 27/Jun/19

$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\$$

Commented byPrithwish sen last updated on 27/Jun/19

$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\$$

Answered by peter frank last updated on 27/Jun/19

$${let}\:{x}=\mathrm{tan}\:\theta\rightarrow\theta=\mathrm{tan}^{−\mathrm{1}} {x} \\$$ $${dx}=\mathrm{sec}\:^{\mathrm{2}} \theta{d}\theta \\$$ $$\int\frac{\mathrm{sec}\:^{\mathrm{2}} \theta{d}\theta}{\mathrm{sec}\:^{\mathrm{2}} \theta} \\$$ $$\theta+{c} \\$$ $$\mathrm{tan}^{−\mathrm{1}} {x}+{c} \\$$ $$\\$$

Commented byPrithwish sen last updated on 27/Jun/19

$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\$$