Question Number 100097 by Dwaipayan Shikari last updated on 24/Jun/20

∫(tanx)^e^(iπ)  dx

Commented byDwaipayan Shikari last updated on 24/Jun/20

∫(tanx)^(−1) dx  ∫cotxdx=log(sinx)+Constant{As  e^(iπ) =−1}