Question Number 100097 by Dwaipayan Shikari last updated on 24/Jun/20

∫(tanx)^e^(iπ) dx

Commented byDwaipayan Shikari last updated on 24/Jun/20

∫(tanx)^(−1) dx ∫cotxdx=log(sinx)+Constant{As e^(iπ) =−1}