Question Number 100404 by PengagumRahasiamu last updated on 26/Jun/20

Commented byPengagumRahasiamu last updated on 26/Jun/20

Thank you

Commented byRasheed.Sindhi last updated on 26/Jun/20

(i)⇒x=((28−y)/(y+2)), (ii)⇒x=((37−z)/(z+3))                  ((28−y)/(y+2))=((37−z)/(z+3))........(iv)  (iii)⇒y=((42−2z)/(z+3))  (iii)&(iv)⇒            ((28−((42−2z)/(z+3)))/(((42−2z)/(z+3))+2))=((37−z)/(z+3))            (((28z+84−42+2z)/(z+3))/((42−2z+2z+6)/(z+3)))=((37−z)/(z+3))           ((30z+42)/(48))=((37−z)/(z+3))           ((5z+7)/8)=((37−z)/(z+3))         5z^2 +22z+21=296−8z         5z^2 +30z−275=0         z^2 +6z−55=0      ( z+11)(z−5)=0       z=−11(descardable),5  x=((37−z)/(z+3))=((37−5)/(5+3))=((32)/8)=4  y=((42−2z)/(z+3))=((42−2(5))/(5+3))=((32)/8)=4  x=4,y=4,z=5  x+(√y)+z=4+(√4)+5=11

Commented bybobhans last updated on 27/Jun/20

x= ((28−y)/(y+2)) = ((37−z)/(z+3)) ∧ y= ((42−2z)/(z+3))  ((28−(((42−2z)/(z+3))))/(((42−2z)/(z+3)) +2)) = ((37−z)/(z+3)) ⇒ ((30z+42)/((z+3)(48))) = ((37−z)/(z+3))  ((30z+42)/(48)) = ((37−z)/(z+3)) ⇒(5z+7)(z+3) = 296−8z  5z^2 +22z+21=296−8z  5z^2 +30z−275=0, z^2 +6z−55=0  (z+11)(z−5)=0 ⇒ { ((z=5)),((y=((42−10)/8)= 4)),((x=((28−4)/6)=4)) :}  ∴ x+(√y) +z = 4+2+5 = 11 ■

Commented byRasheed.Sindhi last updated on 26/Jun/20

Sir bobhans  x,y,z∈Z^+   Then how z=((303)/(13))?

Commented bybramlex last updated on 26/Jun/20

it should be ⇔((30z+42)/(48)) = ((37−z)/(z+3))  ((5z+7)/8) = ((37−z)/(z+3)) ⇔ (5z+7)(z+3)=8(37−z)

Commented byDwaipayan Shikari last updated on 26/Jun/20

x=((28−y)/(y+2))  y=((42−2z)/(z+3))  x=((37−z)/(z+3))  So,((37−z)/(z+3))=((28−((42−2z)/(z+3)))/(((42−2z)/(z+3))+2))⇒((37−z)/(z+3))=((30z+42)/(48))  ((296−8z)/(z+3))=5z+7   ⇒ 296−8z=5z^2 +22z+21  5z^2 +30z−275=0  ⇒z^2 +6z−55   ⇒z=5 or −11  but z≠−11  So;  x=4         y=4  so x+(√y)+z=11

Commented byDwaipayan Shikari last updated on 26/Jun/20

Sir answer will be 11

Commented byDwaipayan Shikari last updated on 26/Jun/20

sir answer is 11. i think you have done some thing mistake

Commented byDwaipayan Shikari last updated on 26/Jun/20

Ohhh  sir you put 2 instead of 5 while finding the value of y

Commented byRasheed.Sindhi last updated on 26/Jun/20

Thank you sir for mentioning  mistake.Now I corrected it.Your  answer is also corret.

Commented bybobhans last updated on 27/Jun/20

sorry sir Rashed. miscalculated