Question Number 10045 by konen last updated on 21/Jan/17

y⟩0 ((3x^2 −3xy+y^2 )/y^2 )=7 ⇒max(x)=?

Answered by mrW1 last updated on 21/Jan/17

3x^2 −3xy+y^2 =7y^2 3x^2 −3xy−6y^2 =0 x^2 −yx−2y^2 =0 (x−2y)(x+y)=0 x=(2y,−y) ⇒max(x)=2y