Question Number 100464 by mathocean1 last updated on 26/Jun/20

A car is driving. It most arrive  at destination situated at 2046 m.  It has travelled 2m the first day,   4 m the second, 8m the thirst, 16  the fourth day ...  How many days is necessary  to   arrive at destination?

Commented byDwaipayan Shikari last updated on 26/Jun/20

2+4+8+16+.....n days=2046  ((2(2^n −1) )/(2−1))=2046    ⇒2^n =1024                                         n=10 days

Commented bymathocean1 last updated on 26/Jun/20

thank you sirs...

Commented bymathocean1 last updated on 26/Jun/20

thank you sirs!

Commented bysmridha last updated on 26/Jun/20

welcome

Answered by smridha last updated on 26/Jun/20

2+2^2 +2^3 +2^4 +....+2^n =2046  ((2(2^n −1))/((2−1)))=2046 ⇒2^n =1024=2^(10)   so n=10days