Question Number 100464 by mathocean1 last updated on 26/Jun/20

A car is driving. It most arrive at destination situated at 2046 m. It has travelled 2m the first day, 4 m the second, 8m the thirst, 16 the fourth day ... How many days is necessary to arrive at destination?

Commented byDwaipayan Shikari last updated on 26/Jun/20

2+4+8+16+.....n days=2046 ((2(2^n −1) )/(2−1))=2046 ⇒2^n =1024 n=10 days

Commented bymathocean1 last updated on 26/Jun/20

thank you sirs...

Commented bymathocean1 last updated on 26/Jun/20

thank you sirs!

Commented bysmridha last updated on 26/Jun/20

welcome

Answered by smridha last updated on 26/Jun/20

2+2^2 +2^3 +2^4 +....+2^n =2046 ((2(2^n −1))/((2−1)))=2046 ⇒2^n =1024=2^(10) so n=10days