Question Number 100703 by bramlex last updated on 28/Jun/20

Commented bybramlex last updated on 28/Jun/20

(1) 2y^2  = 100−40a+4a^2   (2) 16 = (1/2)y^2  ⇒y^2 = 32  (1)∧(2) ⇒4a^2 −40a+100=64   4a^2 −40a+36=0 ; a^2 −10a+9=0  (a−1)(a−9)=0 → { ((a=1)),((a=9 (rejected))) :}  blue area = (a(√2))^2 = 2a^2  = 2  ratio blue area = 2%

Commented bybemath last updated on 28/Jun/20

thank you sir