Question Number 10095 by Tawakalitu ayo mi last updated on 23/Jan/17

Prove that  f(x) = x^2   is continous at x = 2  while f(x) = {_(0         x = 2) ^(x^2        x ≠ 2)    is not continous at x = 2

Answered by sandy_suhendra last updated on 23/Jan/17

(i) f(2)=2^2 =4        lim_(x→2)  x^2  = 2^2 =4       f(x)=x^2  is continuos at x=2       because f(2)=lim_(x→2)  f(x)  (ii) f(2)=0         lim_(x→2_ ) x^2  = 2^2 =4        f(x)=x^2  is not continuous at x=2        because f(2)≠lim_(x→2)  f(x)

Commented byTawakalitu ayo mi last updated on 23/Jan/17

God bless you sir.