Question Number 100986 by Dwaipayan Shikari last updated on 29/Jun/20

Commented bybachamohamed last updated on 29/Jun/20

look this 2=(√(1+(√9)))=(√(1+(√(1+8))))=(√(1+(√(1+(√(64))))))=(√(1+(√(1+(√(1+63)))))) =(√(1+(√(1+(√(1+(√(63^2 ))))))))=(√(1+(√(1+(√(1+(√(1+(63^2 −1))))))))) =(√(1+(√(1+(√(1+(√(1+(√(((63^2 −1))^2 ))))))))))=(√(1+(√(1+(√(1.....+(√(1........∞)))))))) 3=(√9)=(√(1+(√(64))))=(√(1+(√(1+63))))=(√(1+(√(1+(√(63^2 ))))))=(√(1+(√(1+(√(1+(√(1......∞)))))))) 4=(√(16))=(√(1+15))=(√(1+(√(225))))=(√(1+(√(1+224))))=(√(1+(√(1+(√(224^2 ))))))=(√(1+(√(1+(√(1...(√(....(√(1...∞)))))))))) donc pour tout nombre posituve n n=(√(1+(√(1+(√(1+(√(1.....∞)))))))) why?