Question Number 101001 by mhmd last updated on 29/Jun/20

Answered by mr W last updated on 29/Jun/20

Commented bymr W last updated on 29/Jun/20

DQ=(√(4^2 −x^2 ))  ΔAPQ∼ΔDQC  AQ=((3x)/4)  AP=((3(√(4^2 −x^2 )))/4)  ((3(√(4^2 −x^2 )))/4)+((3x)/4)=x  3(√(4^2 −x^2 ))=x  10x^2 =9×16  ⇒x=((12)/(√(10)))=((6(√(10)))/5)≈3.794