Question Number 10101 by Tawakalitu ayo mi last updated on 23/Jan/17

∫ ((z + 2)/(10z + 28)) dz

Commented byprakash jain last updated on 24/Jan/17

=(1/(10))∫((10z+28−8)/(10z+28))dz =(1/(10))∫[1−(8/(10z+28))]dz =(1/(10))[z−(8/(10))ln (10z+28)]+C

Commented byTawakalitu ayo mi last updated on 24/Jan/17

God bless you sir.