Question Number 101051 by aurpeyz last updated on 30/Jun/20

Commented byDwaipayan Shikari last updated on 30/Jun/20

Initial K. E= P.E + work  done by frictional force    (1/2)mv^2 =mgdsin30°+f.d    d=((90)/(29.5))=3.05 metre

Answered by mr W last updated on 30/Jun/20

(1/2)mv^2 −fs=mgs sin θ  s=((mv^2 )/(2(mg sin θ+f)))=((5×6^2 )/(2(5×10×0.5+4.5)))  =3.05 m

Commented byaurpeyz last updated on 06/Jul/20

thanks Sir>