Question Number 101057 by bemath last updated on 30/Jun/20

Find the area bounded the   curves f(x)= ∣x^3 −4x^2 +3x∣ and   x−axis

Answered by john santu last updated on 30/Jun/20

Commented byjohn santu last updated on 30/Jun/20

Area = ∫_0 ^1 (x^3 −4x^2 +3x) dx −∫_1 ^3 (x^3 −4x^2 +3x)dx  = [(1/4)x^4 −(4/3)x^3 +(3/2)x^2  ]_0 ^1 −  [ (1/4)x^4 −(4/3)x^3 +(3/2)x^2 ]_1 ^3    = (5/(12))−((1/4)(80)−(4/3)(26)+(3/2)(8))  = (5/(12))+((104)/3)−32 = (5/(12)) + (8/3)  = ((37)/(12))★

Commented bybemath last updated on 30/Jun/20

thank