Question Number 101082 by 67549972 last updated on 30/Jun/20

The value of e^(log_(10) tan 1°+log_(10) tan 2°+log_(10) tan 3°+...+log_(10) tan 89°) is

Commented byDwaipayan Shikari last updated on 30/Jun/20

e^(log_(10) (tan1°tan2°tan3°.....tan89°)) e^(log_(10) 1) =e^0 =1 {tan1°...tan89°=1

Commented bysmridha last updated on 01/Jul/20

e^(log_(10) [tan1^° .tan2^° .tan3^° ...tan89^° ]) =e^(log_(10) [tan1^° .tan2^° .tan3°...cot3^° .cot2^° .cot1^° ]) =e^(log_(10) 1) =e^0 =1.