Question Number 101172 by I want to learn more last updated on 01/Jul/20

Find the range of the function:        y  =  2  −  x^2  sin(x),      x ≥ 0

Answered by 1549442205 last updated on 07/Jul/20

Since −1≤sinx≤1,so:−x^2 ≤x^2 sinx≤x^2   we infer:2−x^2 ≤ 2−x^2 sinx≤2+x^2   ⇒−∞<y=2−x^2 sinx<+∞  The value domain of y:(−∞;+∞)

Commented byI want to learn more last updated on 01/Jul/20

Sir, is this the same thing as:  Range is all real  numbers.

Commented by1549442205 last updated on 01/Jul/20

the value domain of a function and   the range of a function are same concept