Question Number 10129 by Tawakalitu ayo mi last updated on 26/Jan/17

Write in polar form . (1) 3x − y + 5 = 0 (2) x^2 = (√(x^2 + y^2 ))

Answered by icyfalcon999 last updated on 26/Jan/17

(1): 3(r cos θ)−(r sin θ)+5=0 3r cos θ−r sin θ=−5 r(3cos θ−sin θ)=−5 ((r(3 cos θ−sin θ))/(3 cos θ−sin θ))=((−5)/(3 cos θ−sin θ)) r=(5/(sin θ−3cos θ)) (2): x^2 =(√(x^2 +y^2 )) (rcos θ)^2 =r r^2 cos^2 θ=r ((r^2 cos^2 θ )/r)=(r/r) r cos^2 θ =1 ((r cos^2 θ )/(cos^2 θ ))=(1/(cos^2 θ)) r=(1/(cos^2 θ )) r=sec^2 θ

Commented byTawakalitu ayo mi last updated on 26/Jan/17

God bless you sir.