Question Number 10129 by Tawakalitu ayo mi last updated on 26/Jan/17

Write in polar form .  (1)  3x − y  + 5 = 0  (2)  x^2  = (√(x^2  + y^2 ))

Answered by icyfalcon999 last updated on 26/Jan/17

(1):  3(r cos θ)−(r sin θ)+5=0  3r cos θ−r sin θ=−5  r(3cos θ−sin θ)=−5  ((r(3 cos θ−sin θ))/(3 cos θ−sin θ))=((−5)/(3 cos θ−sin θ))  r=(5/(sin θ−3cos θ))  (2):  x^2 =(√(x^2 +y^2 ))  (rcos θ)^2 =r  r^2 cos^2  θ=r  ((r^2 cos^2 θ )/r)=(r/r)  r cos^2 θ =1  ((r cos^2 θ )/(cos^2 θ ))=(1/(cos^2 θ))  r=(1/(cos^2 θ ))  r=sec^2 θ

Commented byTawakalitu ayo mi last updated on 26/Jan/17

God bless you sir.