Question Number 101291 by Mikael_786 last updated on 01/Jul/20

Answered by mr W last updated on 01/Jul/20

3x^2 −3y^2 (dy/dx)+ay+ax(dy/dx)=0  6x−6y((dy/dx))^2 +(ax−3y^2 )(d^2 y/dx^2 )+2a(dy/dx)=0  with x=a, y=−a:  3a^2 −3a^2 (dy/dx)−a^2 +a^2 (dy/dx)=0  2−2(dy/dx)=0  ⇒(dy/dx)∣_(x=a) =1  6a+6a(1)^2 +(a^2 −3a^2 )(d^2 y/dx^2 )+2a=0  14−2a(d^2 y/dx^2 )=0  ⇒(d^2 y/dx^2 )∣_(x=a) =(7/a)  ⇒answer (E)

Commented byMikael_786 last updated on 02/Jul/20

thank you