Question Number 101303 by Dwaipayan Shikari last updated on 01/Jul/20

i^i^(i.∞)  =?

Commented byDwaipayan Shikari last updated on 01/Jul/20

If there any possible solutions?

Answered by mr W last updated on 01/Jul/20

say i^i^i^(...)   =x  i^x =x  e^((πix)/2) =x  xe^(−((πix)/2)) =1  −((πix)/2)e^(−((πix)/2)) =−((πi)/2)  −((πix)/2)=W(−((πi)/2))  ⇒x=−(2/(πi))W(−((πi)/2))  ⇒x=((2i)/π)W(−((πi)/2))

Commented byDwaipayan Shikari last updated on 01/Jul/20

Thanking you

Commented bymr W last updated on 01/Jul/20