Question Number 101350 by bobhans last updated on 02/Jul/20

Answered by bemath last updated on 02/Jul/20

(x^2 +1)(1−y^2 )dx−xy dy=0 (x^2 +1)(1−y^2 ) dx = xy dy (((x^2 +1))/x) dx = ((y dy)/(1−y^2 )) ∫ (x+(1/x)) dx = −(1/2)∫ ((d(1−y^2 ))/(1−y^2 )) (1/2)x^2 + ln (x) +c = −(1/2)ln(1−y^2 ) ⇔x^2 + 2ln (x) + ln (1−y^2 ) = C x^2 + ln(x^2 (1−y^2 )) = C

Commented bybobhans last updated on 02/Jul/20

yeahhh..★■