Question Number 101362 by bobhans last updated on 02/Jul/20

Commented bybemath last updated on 02/Jul/20

(x^2 +3y^2 )dx+(2xy−x)dy =0  M= x^2 +3y^2 → (∂M/∂y) = 6y  N = 2xy−x→(∂N/∂x) = 2y−1  (∂M/∂y) ≠ (∂N/∂x) ⇐ non exact