Question Number 101418 by john santu last updated on 02/Jul/20

Find 2020 term from series (1/1),(2/1),(1/2),(3/1),(2/2),(1/3),(4/1),(3/2),(2/3),(1/4) ,(5/1),(4/2),... is ___ (A) ((2019)/(2020)) (B) ((61)/4) (C)((63)/1) (D) ((96)/4) (E) ((2020)/(2019))

Commented byPRITHWISH SEN 2 last updated on 02/Jul/20

2020=((4040)/2) = ((4032)/2) +4=((64×63)/2) + 4 =(((61+4−1)(61+4−2))/2)+4 i.e the term is ((61)/4) ans(B) please check sorry it was a typo

Commented bybemath last updated on 02/Jul/20

why (((61+4−1)(61+4−2))/2)− 4 ?

Commented bybramlex last updated on 02/Jul/20

what is the pattern on that series sir?

Commented byRKT last updated on 03/Jul/20

I cannot tell you how he get the solution in 4 to 5 steps, but solution in two pages is here

Commented byRKT last updated on 03/Jul/20

Commented byRKT last updated on 03/Jul/20