Question Number 101491 by bobhans last updated on 03/Jul/20

Commented bybemath last updated on 03/Jul/20

(√((2x^2 +17x−(x^2 +5x−36))/(x(x−4)))) − (√((x^2 −5x+4+x)/(x(x−4)))) = (8/((√5) )) (√((x^2 +12x+36)/(x(x−4)))) −(√((x^2 −4x+4)/(x(x−4)))) = (8/(√5)) ((∣x+6∣−∣x−2∣)/(√(x(x−4)))) = (8/(√5)) equation defined on x(x−4)> 0 → x<0 or x>4 case(1) x<0 ∩ x<−6 ⇒ ((−x−6+x−2)/(√(x(x−4)))) = (8/(√5)) has no solution case(2) x>4 ⇒ ((x+6−x+2)/(√(x^2 −4x))) = (8/(√5)) (√(x^2 −4x)) = (√5) ⇒x^2 −4x−5=0 (x−5)(x+1) = 0 x = 5 (solution) x=−1(rejected)

Commented bybobhans last updated on 03/Jul/20

how sir??