Question Number 10172 by konen last updated on 28/Jan/17

x^x =2^(24)  , y^y =3^(18) ⇒((2y+3x)/(y−x))=?

Answered by ridwan balatif last updated on 28/Jan/17

x^x =2^(24)   x^x =(2^3 )^8   x^x =8^8   x=8  y^y =3^(18)   y^y =(3^2 )^9   y^y =9^9   y=9  ((2y+3x)/(y−x))=((2×9+3×8)/(9−8))=42