Question Number 10204 by gogel last updated on 30/Jan/17

x^2 p^2 +xyp−6y^2 =0

Answered by FilupSmith last updated on 30/Jan/17

solve for x:     a=p^2 , b=yp, c=−6y^2   ∴ ax^2 +bx+c=0  ∴ x=((−b±(√(b^2 −4ac)))/(2a))  ∴ x=((−yp±(√(y^2 p^2 +24p^2 y^2 )))/(2p^2 ))  ∴ x=((−yp±(√(25p^2 y^2 )))/(2p^2 ))  ∴ x=((−yp±5py)/(2p^2 ))  ∴ x=(((−1±5)y)/(2p))  x = −((3y)/p), ((2y)/p)