Question Number 102139 by mathocean1 last updated on 06/Jul/20

We have 4 boys and 2 girls. we choose at random and simultaneous 2 boys and 1 girl to for a group. 1) How many possibilities do we have?

Commented byprakash jain last updated on 07/Jul/20

^4 C_2 ×^2 C_1 =24.

Answered by geoplitz last updated on 06/Jul/20

Boys: b_1 , b_2 , b_3 , b_4 Girls: g_1 , g_2 With b_1 and b_2 , we have 2 possible groups. (b_1 , b_2 ) → 2 So, we have (b_1 , b_2 ) → 2 (b_2 , b_3 ) → 2 (b_1 , b_3 ) → 2 (b_2 , b_4 ) → 2 (b_1 , b_4 ) → 2 (b_3 , b_4 ) → 2 So, we have 12 possibilities. 2 + 2 + 2 + 2 + 2 + 2 = 12