Question Number 102348 by mohammad17 last updated on 08/Jul/20

Answered by mr W last updated on 08/Jul/20

a_n =(((2n+1)^2 +1)/((2n+1)^2 −1))  =1+(2/((2n+1)^2 −1))  =1+(2/((2n)(2n+2)))  =1+(1/2)×(1/(n(n+1)))  =1+(1/2)((1/n)−(1/(n+1)))  Σ_(n=1) ^(49) a_n =49+(1/2)((1/1)−(1/(50)))=49+((49)/(100))=49.49

Commented bymohammad17 last updated on 08/Jul/20

nice sir thank you