Question Number 102382 by Ar Brandon last updated on 08/Jul/20

x^2 ∙(dy/dx)=x^2 +xy+y^2

Answered by PRITHWISH SEN 2 last updated on 08/Jul/20

put y=vx  (dy/dx) = v+x(dv/dx)  and the equation changes to  (dv/(1+v^2 )) = (dx/x)  tan^(−1) ((y/x))=lnCx     C = const.  y=xtan {ln∣Cx∣}

Commented byAr Brandon last updated on 08/Jul/20

Oh thanks, I didn't notice that.