Question Number 102444 by bemath last updated on 09/Jul/20

find the area bounded the  curves y^2 = 36+12x and   y^2 =16−8x

Answered by bemath last updated on 09/Jul/20

⇔ ((y^2 −36)/(12)) = ((16−y^2 )/8)  (y^2 /(12))−3 = 2−(y^2 /8)  ((5y^2 )/(24)) − 5 = 0 ⇒Δ=((4.5.5)/(24)) = ((25)/6)  Area = ((Δ(√Δ))/(6.a^2 )) = ((((25)/6).(5/(√6)))/(6.(((25)/(24^2 )))))  =((125)/(6(√6))) × ((24.24)/(6.25)) = ((80)/(√6))  = ((40(√6))/3) .