Question Number 102635 by ketto255 last updated on 10/Jul/20

Answered by bobhans last updated on 10/Jul/20

sin (90^o −θ) = cos θ =± (√(1−sin ^2 θ)) = ±(√(1−(2/(25)))) = ± ((√(23))/5)

Answered by Rasheed.Sindhi last updated on 10/Jul/20

sin(90−θ)=cos θ sin^2 θ+cos^2 θ =1 (((√2)/5))^2 +cos^2 θ =1 cos θ=±(√(1−(2/(25))))=±((√(23))/5) sin(90−θ)=±((√(23))/5) ★