Question Number 102796 by saorey0202 last updated on 11/Jul/20

The angle between the vectors  2i+3j+k  and  2i−j−k  is

Answered by bramlex last updated on 11/Jul/20

cos β = ((a^→ .b^→ )/(∣a^→ ∣ ∣b^→ ∣)) = ((4−3−1)/(∣a^→ ∣ ∣b^→ ∣))  β = 90^o