Question Number 10289 by konen last updated on 02/Feb/17

((9−x^2 )/x)+3=((x−3)/3)⇒Σx=?

Answered by ridwan balatif last updated on 02/Feb/17

((9−x^2 )/x)+3=((x−3)/3)  ((9−x^2 )/x)=((x−3)/3)−(9/3)  ((9−x^2 )/x)=((x−12)/3)  27−3x^2 =x^2 −12x  0=4x^2 −12x−27  Σx=((−(−12))/4)=3