Question Number 103043 by bemath last updated on 12/Jul/20

 { ((x^2 +2xy+21=6x)),((y^2 +2yz−8=6y)),((z^2 +2zx−4=6z)) :}  find x+y+z

Answered by maths mind last updated on 12/Jul/20

⇒(x+y+z)^2 −6(x+y+z)+9=0

Commented bybemath last updated on 12/Jul/20

coll ,😎😎😎

Commented byRasheed.Sindhi last updated on 12/Jul/20

Nice!

Answered by Dwaipayan Shikari last updated on 12/Jul/20

(x+y+z)^2 −6(x+y+z)+9=0  x+y+z=3