Question Number 103155 by 9027201563 last updated on 13/Jul/20

If cos^(−1) x+cos^(−1) y+cos^(−1) z+cos^(−1) u=2π,  then  x^(1999) +y^(2000) +z^(2001) +u^(2002) =

Commented by9027201563 last updated on 13/Jul/20

solution needed urgently

Commented byprakash jain last updated on 13/Jul/20

I dont think you can get a unique  answer  assuming  cos^(−1) x=cos^(−1) y=π  cos^(−1) z=cos^(−1) u=0  x=−1,y=−1,z=1,u=1  sum=2  cos^(−1) x=cos^(−1) y=cos^(−1) z=cos^(−1) u=(π/2)  x=y=z=u=0  sum=0