Question Number 103168 by mohammad17 last updated on 13/Jul/20

The particular solution of differential equation   of (dy/dx)+(y/x)=k is y=(1/x)+2x thus ,whats the value of k ?

Answered by bemath last updated on 13/Jul/20

IF u(x)= e^(∫ (dx/x))  = e^(ln(x))  = x  x.(dy/dx) + y = kx   (d/dx) (xy) = kx   xy = (1/2)kx^2  + C   y = ((kx)/2) + (C/x) , then ((kx)/2) = 2x  ∴ k = 4

Commented bymohammad17 last updated on 13/Jul/20

thank you sir