Question Number 10317 by Tawakalitu ayo mi last updated on 03/Feb/17

Solve for x.  3^(2x)  = 18x  please i need workings.

Answered by mrW1 last updated on 03/Feb/17

(3^2 )^x =18x  9^x =18x  e^(xln 9) =18x  1=((18)/(−ln 9))(−xln 9)e^(−xln 9)   (−xln 9)e^(−xln 9) =−((ln 9)/(18))  −xln 9=W(−((ln 9)/(18))) with W=Lambert W function  x=−((W(−((ln 9)/(18))))/(ln 9))=−((W(−0.122068))/(2.197225))  = { ((−((−0.140479)/(2.197225))=0.063935)),((−((−3.295837)/(2.197225))=1.5)) :}

Commented byTawakalitu ayo mi last updated on 04/Feb/17

God bless you sir.

Answered by arge last updated on 04/Feb/17

    log 3^(2x) =log18x  2xlog 3=log 18+log x    log x=y    0.95x=1.26+y  x=((1.26+y)/(0.95))