Question Number 10317 by Tawakalitu ayo mi last updated on 03/Feb/17

Solve for x. 3^(2x) = 18x please i need workings.

Answered by mrW1 last updated on 03/Feb/17

(3^2 )^x =18x 9^x =18x e^(xln 9) =18x 1=((18)/(−ln 9))(−xln 9)e^(−xln 9) (−xln 9)e^(−xln 9) =−((ln 9)/(18)) −xln 9=W(−((ln 9)/(18))) with W=Lambert W function x=−((W(−((ln 9)/(18))))/(ln 9))=−((W(−0.122068))/(2.197225)) = { ((−((−0.140479)/(2.197225))=0.063935)),((−((−3.295837)/(2.197225))=1.5)) :}

Commented byTawakalitu ayo mi last updated on 04/Feb/17

God bless you sir.

Answered by arge last updated on 04/Feb/17

log 3^(2x) =log18x 2xlog 3=log 18+log x log x=y 0.95x=1.26+y x=((1.26+y)/(0.95))