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Question Number 103195 by bemath last updated on 13/Jul/20

893x = 266 (mod 2432)

$$\mathrm{893}{x}\:=\:\mathrm{266}\:\left({mod}\:\mathrm{2432}\right) \\ $$

Commented by Rasheed.Sindhi last updated on 29/Jul/20

⇒47x≡14(mod 128)

$$\Rightarrow\mathrm{47}{x}\equiv\mathrm{14}\left({mod}\:\mathrm{128}\right) \\ $$

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