Question Number 103347 by I want to learn more last updated on 14/Jul/20

Commented byI want to learn more last updated on 14/Jul/20

Commented byTawa11 last updated on 15/Sep/21

nice

Answered by 1549442205 last updated on 14/Jul/20

R_1 =12cm,R_2 =8cm,r=2 cm  The length of the arc QR is  p_1 =((2πR_1 )/(360))×80=((2π×12×8)/(36))=((16π)/3)(cm)  The length of the arc PS is  p_2 =((2πR_2 )/(360))×80=((2π×8×8)/(36))=((32π)/9)(cm)  The length of two semicircles is p_3 =2πr=4π(cm)  The perimeter of shape is  P=p_1 +p_2 +p_3 =((16𝛑)/3)+((32𝛑)/9)+4𝛑=((116𝛑)/9)(cm)  b)The area of the sector OQR is  S_1 =πR_1 ^2 ×((80)/(360))=((144×8π)/(36))=72π(cm^2 )  The area of the sector OPS is  S_2 =πR_2 ^2 ×((80)/(360))=((64×8π)/(36))=((128π)/9) (cm^2 )  The area of two semicircles is  S_3 =πr^2 =4π(cm^2 )  The are of shape is   S=(S_1 −S_2 )+S_3 =72𝛑−((128𝛑)/9)−4𝛑=((484𝛑)/9)(cm^2 )

Commented byI want to learn more last updated on 14/Jul/20

Thanks sir, i appreciate