Question Number 1034 by 123456 last updated on 21/May/15

x=i+f,i∈N,f∈[0,1) x^2 =(i+f)^2 =i^2 +2if+f^2 x∈R_+ i+2f=2⇒x^2 =2i+f^2 2if=0⇒x^2 =i^2 +f^2

Answered by prakash jain last updated on 21/May/15

2if=0⇒i=0∨f=0 ∵f<1, i+2f=2 ⇒i>0 f=0,i=2 x^2 =2^2 ⇒x=±2